make the order of the returned jobs slice deterministic (#652)

scheduler.go

@@ -228,6 +228,17 @@ func (s *scheduler) selectAllJobsOutRequest(out allJobsOutRequest) {
 		outJobs[counter] = s.jobFromInternalJob(j)
 		counter++
 	}
+	slices.SortFunc(outJobs, func(a, b Job) int {
+		aID, bID := a.ID().String(), b.ID().String()
+		switch {
+		case aID < bID:
+			return -1
+		case aID > bID:
+			return 1
+		default:
+			return 0
+		}
+	})
 	select {
 	case <-s.shutdownCtx.Done():
 	case out.outChan <- outJobs:

scheduler_test.go

@@ -1635,3 +1635,32 @@ func TestScheduler_OneTimeJob(t *testing.T) {
 		})
 	}
 }
+
+func TestScheduler_Jobs(t *testing.T) {
+	tests := []struct {
+		name string
+	}{
+		{
+			"order is equal",
+		},
+	}
+
+	for _, tt := range tests {
+		t.Run(tt.name, func(t *testing.T) {
+			s := newTestScheduler(t)
+
+			for i := 0; i <= 20; i++ {
+				_, err := s.NewJob(
+					DurationJob(time.Second),
+					NewTask(func() {}),
+				)
+				require.NoError(t, err)
+			}
+
+			jobsFirst := s.Jobs()
+			jobsSecond := s.Jobs()
+
+			assert.Equal(t, jobsFirst, jobsSecond)
+		})
+	}
+}